Hello student,
as per your query you want to add 4,four times, then you will get 4*4 which is equal to 16.
So
4 + 4 + 4 + 4 = 16 .
hope this will help you to understand.
Question : $\left(4 x^3 y-6 x^2 y^2+4 x y^3-y^4\right)$ can be expressed as:
Option 1: $(x+y)^4-x^4$
Option 2: $(x+y)^4-y^4$
Option 3: $(x-y)^4-x^4$
Option 4: $x^4-(x-y)^4$
Question : Simplify: $(3x-2y)(3x+2y)(9x^2+4y^2)$
Option 1: $81x^4+16y^4$
Option 2: $81y^4-16x^4$
Option 3: $81y^4+16x^4$
Option 4: $81x^4-16y^4$
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