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Question : 60 discs each of diameter 21 cm and thickness $\frac{1}{3}$ cm are stacked one above the other to form a right circular cylinder. What is its volume in m3 if $\pi=\frac{22}{7}$?

Option 1: 7.62 × 10–2

Option 2: 8.05 × 10–3

Option 3: 6.93 × 10–3

Option 4: 4.25 × 10–2


Team Careers360 6th Jan, 2024
Answer (1)
Team Careers360 20th Jan, 2024

Correct Answer: 6.93 × 10–3


Solution : Given,
The diameter of the disc = 21 cm
⇒ Radius of the disc, $r$ = $\frac{21}{2}$ cm
Height of 60 discs if they stacked one above the other = 60 × $\frac{1}{3}$ = 20 cm
So, the volume of the cylinder
= $\pi r^2h$
= $\frac{22}{7} × \frac{21}{2} × \frac{21}{2}× 20$
= $6930$ cm3
As we know,
1 cm3 = 10–6 m
So, the volume = 6930 cm3 = 6.93 × 10–3 m3
Hence, the correct answer is 6.93 × 10–3 m3.

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