Question : a3 + b3 + c3 = 3abc if _________.
Option 1: a = b = c
Option 2: a + b + c = 0
Option 3: a + b + c = 1
Option 4: a + b + c = –1
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Correct Answer: a + b + c = 0
Solution : We know that a3 + b3 + c3 = (a + b + c) (a2 + b2 + c2 – ab – bc – ca) + 3abc So, a3 + b3 + c3 = 3abc when (a + b + c) = 0 Hence, the correct answer is (a + b + c) = 0.
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Question : If a + b + c = 0, the value of (a3 + b3 + c3) is:
Option 1: abc
Option 2: 2abc
Option 3: 3abc
Option 4: 0
Question : What is the value of ${a}^3+{b}^3+{c}^3$ if $(a+b+c)=0$?
Option 1: $a^2+b^2+c^2-3abc$
Option 2: $0$
Option 3: $3abc$
Option 4: $a^2+b^2+c^2-ab-bc-ca$
Question : What is the value of a2 + b2 + c2 – 2ab – 2bc + 2ca?
Option 1: (2a + b + c)2
Option 2: (a – b + c)2
Option 3: (a – b – 2c)2
Option 4: (a + 2b – c)2
Question : If a + b + c = 1, ab + bc + ca = –22 and abc = –40, then what is the value of a3 + b3 + c3 ?
Option 1: 67
Option 2: –53
Option 3: –51
Option 4: 27
Question : What is the possible value of (a + b + c) – 3, if a2 + b2 + c2 = 9 and ab + bc + ca = 8?
Option 1: 5
Option 2: 3
Option 3: 9
Option 4: 2
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