Question : A alone can do a work in 14 days. B alone can do the same work in 28 days. C alone can do the same work in 56 days. They started the work together and completed the work such that B was not working in the last 2 days and A did not work in the last 3 days. In how many days (total) was the work completed?
Option 1: $\frac{82}{7}$ days
Option 2: $\frac{79}{7}$ days
Option 3: $\frac{65}{7}$ days
Option 4: $\frac{72}{7}$ days
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Correct Answer: $\frac{72}{7}$ days
Solution : Given: A alone can do a work in 14 days. B alone can do the same work in 28 days. C alone can do the same work in 56 days. Use the formula, Total work = efficiency × time.
For the last 2 days, B has not worked, while A has not worked for the last 3 days. Let the entire work be finished in $x$ days. ⇒ $4(x–3)+2(x–2)+x=56$ ⇒ $4x–12+2x–4+x=56$ ⇒ $7x=56+16$ ⇒ $7x=72$ ⇒ $x=\frac{72}{7}$ days Hence, the correct answer is $\frac{72}{7}$ days.
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Question : A can do $\frac{1}{3}$rd of a piece of work in 32 days, B can do $37 \frac{1}{2}$% of the same work in 24 days, while C can do 60% of the same work in 48 days. B and C together started and worked for x days. After x days, B left and A joined C and together, completed the remaining work in (x + 8) days. If the ratio of the work done by (B + C) together to the work done by (A + C) together is 9 : 11, then what fraction of the same work can be completed by C alone in 3.5x days?
Option 1: $\frac{18}{25}$
Option 2: $\frac{4}{5}$
Option 3: $\frac{7}{10}$
Option 4: $\frac{3}{4}$
Question : To do certain work, Ajay and Bharat work on alternate days, with Bharat starting the work on the first day. Ajay can finish the work alone in 32 days. If the work gets completed in exactly 8 days, then Bharat alone can finish 7 times the same work in _______ days.
Option 1: $\frac{28}{8}$
Option 2: $4$
Option 3: $\frac{32}{7}$
Option 4: $32$
Question : A can do a piece of work in 9 days, while B can do it in 12 days. A and B together can do the work in:
Option 1: $5\frac{1}{7}$ days
Option 2: $5\frac{2}{7}$ days
Option 3: $6\frac{1}{7}$ days
Option 4: $6\frac{2}{7}$ days
Question : A alone can do $\frac{2}{5}$ of a work in 12 days. B is 25% more efficient than A. C alone can do the same work in 12 days less than B. D is 25% less efficient than C. If they all work together, then the work will be completed in how many days?
Option 1: $\frac{240}{53}$ days
Option 2: $\frac{180}{43}$ days
Option 3: $\frac{200}{51}$ days
Option 4: $\frac{300}{47}$ days
Question : A can do $\frac{1}{3}$ of a work in 30 days. B can do $\frac{2}{5}$ of the same work in 24 days. They worked together for 20 days. C completed the remaining work in 8 days. Working together A, B and C will complete the same work in:
Option 1: 15 days
Option 2: 10 days
Option 3: 18 days
Option 4: 12 days
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