Question : A, B, and C are three points such that AB = 9 cm, BC = 11 cm, and AC = 20 cm. The number of circles passing through points A, B, and C is:
Option 1: 2
Option 2: 0
Option 3: 1
Option 4: 3
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Correct Answer: 0
Solution : Given: A, B, and C are three points such that AB = 9 cm, BC = 11 cm, and AC = 20 cm. Here, AB + BC = 9 + 11 = 20 = AC So, no triangles can be formed using the given three sides. Therefore, no circle will pass through the given three points. Hence, the correct answer is 0.
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Question : If $\frac{a^{2} - bc}{a^{2}+bc}+\frac{b^{2}-ca}{b^{2}+ca}+\frac{c^{2}-ab}{c^{2}+ab}=1$, then the value of $\frac{a^{2}}{a^{2}+bc}+\frac{b^{2}}{b^{2}+ac}+\frac{c^{2}}{c^{2}+ab}$ is:
Option 1: 0
Option 2: 1
Option 3: –1
Option 4: 2
Question : $\triangle ABC$ is an isosceles triangle with AB = AC = 15 cm and an altitude from A to BC of 12 cm. The length of side BC is:
Option 1: 9 cm
Option 2: 12 cm
Option 3: 18 cm
Option 4: 20 cm
Question : A circle is inscribed in a ΔABC having sides AB = 16 cm, BC = 20 cm, and AC = 24 cm, and sides AB, BC, and AC touch circle at D, E, and F, respectively. The measure of AD is:
Option 1: 10 cm
Option 2: 20 cm
Option 3: 6 cm
Option 4: 14 cm
Question : In a $\triangle$ABC, DE||BC, D and E lie on AB and AC, respectively. If AB = 7 cm and BD = 3 cm, then find BC : DE.
Option 1: 2 : 3
Option 2: 3 : 2
Option 3: 3.5 : 2
Option 4: 7 : 2
Question : In $\triangle$ABC, D and E are points on the sides BC and AB, respectively, such that $\angle$ACB = $\angle$ DEB. If AB = 12 cm, BE = 5 cm and BD : CD = 1 : 2, then BC is equal to:
Option 1: $8 \sqrt{3}$ cm
Option 2: $5 \sqrt{5}$ cm
Option 3: $6 \sqrt{5}$ cm
Option 4: $6 \sqrt{3}$ cm
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