Question : A, B, and C can finish a work in 15 days working alternately in the same order. The efficiency of A is the same as that of B and the efficiency of C is equal to that of A. In how many days will the work be finished if they work alternately in the order C, A, and B?
Option 1: 12
Option 2: 14
Option 3: 15
Option 4: 16
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Correct Answer: 15
Solution : The efficiency of A is the same as that of B and the efficiency of C is equal to that of A. Let the efficiency of B is $x$. Then the efficiency of A is $x$. Also, the efficiency of C would be $x$. Since the efficiency is the same, A, B, and C working in any order would take 15 days to complete the work. Hence, the correct answer is 15.
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Question : A and B together can finish a job in 24 days, while A, B, and C together can finish the same job in 8 days. C alone will finish the job in:
Option 1: 12 days
Option 2: 14 days
Option 3: 16 days
Option 4: 24 days
Question : A, B, and C can do work separately in 16, 32, and 48 days, respectively. They started the work together, but B left off eight days and C six days before the completion of the work. In what time is the work finished?
Option 1: 10 days
Option 2: 9 days
Option 3: 12 days
Option 4: 14 days
Question : A, B and C can work separately in 18, 36 and 54 days. They started the work together, but B and C left 5 days and 10 days, respectively, before the completion of the work. In how many days was the work finished?
Option 1: 15 days
Option 2: 13 days
Option 3: 14 days
Option 4: 12 days
Question : A can do a piece of work in 20 days and B in 15 days. With the help of C, they finish the work in 5 days. C can alone do the work in:
Option 1: 5 days
Option 2: 6 days
Option 3: 10 days
Question : To do a certain work, the ratio of the efficiencies of A and B is 7 : 5. Working together, they can complete the same work in $17 \frac{1}{2}$ days. A alone will complete 60% of the same work in:
Option 1: 18 days
Option 2: 15 days
Option 4: 21 days
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