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a body travels to 200 centimetre in first 2s 220 CM in next 4 second with deceleration the velocity of the body at end of the 7th second is answer is 10 cm per second


ksomuvasanth 23rd Aug, 2020
Answer (1)
Prabhav Sharma 23rd Aug, 2020

Hello,

The displacement of a body is given by s = ut + 1/2 * a * t^2

Case 1: When body covers 200 cm in 2s

s = ut + 1/2 * a * t^2

200 = u * 2 + 1/2 * a * 2^2

u + a = 100 (Equation 1)

Case 2: When body covers 220 cm in next 4s, therefore in total it will cover (200+220 = 420 cm) in (2+4 = 6 sec)

s = ut + 1/2 * a * t^2

420 = u*6 + 1/2 * a * 6^2

u + 3a = 70 (Equation 2)

Solving Equation 1 and Equation 2, we get:

u = 115 cm/s and a = -15 cm/s^2

Now, v = u + at

At the end of 7 seconds, t = 7, Substituting the values in above equation, we get:

v = 115 - 15 * 7

v = 10 cm/sec (Answer)


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