Hi Aman,
This is the solution.
Each wiper sweeps a sector of a circle. Radius $r=25 \mathrm{~cm}$, angle $=150^{\circ}$ Area cleaned by one wiper $ =\frac{150}{360} \pi r^2=\frac{5}{12} \pi(25)^2=\frac{3125 \pi}{12} \mathrm{~cm}^2 $ Since two wipers do not overlap, Total cleaned area $ =2 \times \frac{3125 \pi}{12}=\frac{3125 \pi}{6} \mathrm{~cm}^2 \approx 1636 \mathrm{~cm}^2 . $
Question : A square park has sides of length 18 cm. A 1 cm wide path along the edges is inside it. What is the area of the path?
Option 1: 92 cm2
Option 2: 68 cm2
Option 3: 180 cm2
Option 4: 76 cm2
Question : If the length of a certain rectangle is decreased by 4 cm and breadth is increased by 2 cm, it would result in a square of the same area. What is the perimeter of the original rectangle?
Option 1: 15 cm
Option 2: 24 cm
Option 3: 20 cm
Option 4: 10 cm
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