Question : A circle and a square have the same area. The ratio of the side of the square to the radius of the circle will be:
Option 1: $\sqrt\pi:1$
Option 2: $1:\sqrt\pi$
Option 3: $(\pi)^2:1$
Option 4: $1:\sqrt2\pi$
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Correct Answer: $\sqrt\pi:1$
Solution : Given: A circle and a square have the same area. We know that the area of the square is $a^2$, where $a$ is its side, and the area of the circle is $\pi\times r^2$, where $r$ is its radius. According to the question, $\pi\times r^2=a^2$ ⇒ $\pi=\frac{a^2}{r^2}$ ⇒ $\sqrt\pi=\frac{a}{r}$ The ratio of the square's side to the circle's radius is $\sqrt\pi:1$. Hence, the correct answer is $\sqrt\pi:1$.
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Question : The areas of a circle and a square are the same. The ratio of the side of the square to the radius of the circle is:
Option 1: $2\pi :1$
Option 2: $1:\sqrt{\pi}$
Option 3: $\sqrt{\pi}:1$
Option 4: $1:\pi$
Question : A square and a regular hexagon are drawn such that all the vertices of the square and the hexagon are on a circle of radius $r$ cm. The ratio of area between the square and the hexagon is:
Option 1: $3: 4$
Option 2: $4:3\sqrt{3}$
Option 3: $\sqrt{2}:\sqrt{3}$
Option 4: $1:\sqrt{2}$
Question : ABCD is a square inscribed in a circle of radius $r$. Then the total area (in square units) of the portions of the circle lying outside the square is:
Option 1: $\pi (r^{2}-4)$
Option 2: $2\pi (r ^{2}-1)$
Option 3: $\pi^{2} r(r-7)$
Option 4: $r^{2}(\pi -2)$
Question : In a circle of radius 3 cm, two chords of length 2 cm and 3 cm lie on the same side of a diameter. What is the perpendicular distance between the two chords?
Option 1: $\frac{4 \sqrt{3}-3 \sqrt{2}}{2}$ cm
Option 2: $\frac{4 \sqrt{2}-3 \sqrt{3}}{2}$ cm
Option 3: $\frac{4 \sqrt{2}-3 \sqrt{3}}{3}$ cm
Option 4: $\frac{4 \sqrt{2}-3 \sqrt{3}}{4}$ cm
Question : Two equal circles intersect so that their centres and the points at which they intersect form a square of side 1 cm. The area (in cm2) of the portion that is common to the circle is:
Option 1: $\frac{\pi }{4}$
Option 2: $\frac{\pi }{2}-1$
Option 3: $\frac{\pi }{5}$
Option 4: $(\sqrt{2}-1)$
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