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A concave lens of glass, refractive index 1.5, has both surfaces of the samr radius of curvature R. on immersion in a medium of refractive index 1.75, it will behave as a...


manojdhami293 20th Jun, 2020
Answer (1)
Mounika Sonti 20th Jun, 2020

Hello!!!

Hope you are doing great!!!

Consider refraction of light from infinity at first surface,

μ 2/v - μ 1/u = μ 2- μ 1/R

1.5/v1 - 1.75/-∞   = 1.5-1.75/-R

Consider refraction of this image from second surface

1.75/v2 - 1.5/v1 = 1.75-1.5/R

v2=3.5R

The image of light coming from infinity.

It is converging since focal length is positive.

Hope it helps!!!

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