Question : A group of men committed to completing a task in 20 days. The work was completed in 40 days because 5 workers did not come for work. Determine the number of men who originally agreed to do the work.
Option 1: 15
Option 2: 10
Option 3: 12
Option 4: 18
Correct Answer: 10
Solution : Let the men who completed the work be $x$. Absent workers = 5 The work is completed in 40 days. Earlier the work was to be completed in 20 days. We know that, $M_1D_1= M_2D_2$ ⇒ $x\times40=(x+5)\times20$ ⇒ $40x=20x+100$ ⇒ $20x=100$ $\therefore x=5$ So, the number of men who originally agreed to do the work = $(x+5)=5+5=10$ Hence, the correct answer is 10.
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Question : 24 men can complete a work in 15 days. How many men are needed to complete the same work in 10 days?
Option 1: 16
Option 2: 20
Option 3: 36
Option 4: 25
Question : 60 men can complete a work in 40 days. They start to work together but after every 10 days, 5 men leave work. In how many days will the work be completed?
Option 1: 47.5
Option 2: 49.5
Option 3: 42.5
Option 4: 45.5
Question : A and B can do a piece of work in 25 days. B alone can do $66 \frac{2}{3}$% of the same work in 30 days. In how many days can A alone do $\frac{4}{15}$th part of the same work?
Option 1: 18
Option 2: 15
Option 4: 20
Question : 3 men and 7 women can do a job in 5 days, while 4 men and 6 women can do it in 4 days. The number of days required for a group of 10 women working together, at the same rate as before, to finish the same job is:
Option 1: 30 days
Option 2: 36 days
Option 3: 40 days
Option 4: 20 days
Question : A can do work in 12 days and B in 24 days. If they work together, in how many days will they finish the work?
Option 1: 12 days
Option 2: 20 days
Option 3: 15 days
Option 4: 8 days
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