Question : A hemispherical dome of a building needs to be painted. If the circumference of the base of the dome is 154 cm, then find the cost of painting it if the cost of painting is INR 4 per 100 cm². (Use$ ~\pi=\frac{22}{7}$).

Option 1: INR 150.92

Option 2: INR 150.66

Option 3: INR 105.29

Option 4: INR 105.66

Question : A hemispherical bowl is made of 1 cm thick steel. The inside radius of the bowl is 4 cm. The volume of the steel (in cm³) used in making the bowl is:

Option 1: $40\frac{2}{3}\pi$

Option 2: $27\frac{1}{3}\pi$

Option 3: $41\frac{1}{3}\pi$

Option 4: $35\frac{1}{3}\pi$

Question : The dome of a residential tower is in the form of a hemisphere with a radius of 560 cm. Find the cost of painting it at the rate of Rs. 25 per m². (Take $\pi=\frac{22}{7}$)

Option 1: Rs. 4928

Option 2: Rs. 4982

Option 3: Rs. 4298

Option 4: Rs. 4289

Question : A hemispherical bowl has an internal radius of 6 cm. The internal surface area would be: (Take $\pi =3.14$)

Option 1: 225 cm²

Option 2: 400 cm²

Option 3: 289.75 cm²

Option 4: 226.08 cm²

Question : The sides of a rhombus are 10 cm each and the diagonal measures 16 cm. The area of the rhombus is:

Option 1: 96 sq. cm

Option 2: 160 sq. cm

Option 3: 100 sq. cm

Option 4: 40 sq. cm