Question : A number is greater than 58 times its reciprocal by $\frac{3}{4}$. What is the number?
Option 1: –8
Option 2: 12
Option 3: –12
Option 4: 8
New: SSC CGL 2025 Tier-1 Result
Latest: SSC CGL complete guide
Suggested: Month-wise Current Affairs | Upcoming Government Exams
Correct Answer: 8
Solution : Let the number be $x$. According to the question, $\frac{58}{x}+\frac{3}{4}=x$ $\Rightarrow 4x^2-3x-232=0$ $\Rightarrow 4x^2-32x+29x-232=0$ $\Rightarrow 4x(x-8)+29(x-8)=0$ $\Rightarrow (4x+29)(x-8) =0$ $\Rightarrow (4x+29)=0$ or $(x-8) =0$ $\therefore x=\frac{-29}{4},8$ Hence, the correct answer is 8.
Candidates can download this ebook to know all about SSC CGL.
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Question : A fraction is greater than its reciprocal by $\frac{9}{20}$. What is the fraction?
Option 1: $\frac{5}{4}$
Option 2: $\frac{4}{5}$
Option 3: $\frac{3}{4}$
Option 4: $\frac{4}{3}$
Question : A fraction is greater than twice its reciprocal by $\frac{7}{15}$. What is the fraction?
Option 1: $\frac{3}{5}$
Option 2: $\frac{5}{3}$
Question : If $A=\frac{\sqrt{0.0004} \times \sqrt[3]{0.000008}}{\sqrt[4]{16000} \times \sqrt[3]{125000} \times \sqrt[4]{810}}$ and $B=\frac{\sqrt[3]{0.729} \times \sqrt[4]{0.0016}}{\sqrt{0.16}}$, then what is $A \times B$?
Option 1: $6 \times 10^{–7}$
Option 2: $\frac{7}{4} \times 10^{–8}$
Option 3: $5 \times 10^{–8}$
Option 4: $\frac{7}{3} \times 10^{–7}$
Question : The value of $5–\frac{8+2\sqrt{15}}{4}–\frac{1}{8+2\sqrt{15}}$ is equal to:
Option 1: $\frac{1}{4}$
Option 2: $1$
Option 3: $\frac{2}{3}$
Option 4: $\frac{1}{2}$
Question : Directions: By interchanging the given two signs and numbers, which of the following equations will be correct? + and ×, 1 and 2
Option 1: 8 × 3 – 4 ÷ 2 + 1 = 7
Option 2: 2 × 3 – 8 ÷ 1 + 9 = 18
Option 3: 8 × 3 – 4 ÷ 2 + 1 = 3
Option 4: 2 × 3 – 8 ÷ 1 + 2 = 5
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile