Hello,

To understand and solve this question, first draw the parallelogram with its diagonal  on a piece of paper. You will see that the parallelogram is divided into two triangles of equal area.

Now Multiply are of one triangle by 2,

We will get,

√ [s (s-a) (s-b) (s-c) ]  x 2

where s = ( 6 + 4 + 8 ) divided by 2

s =  18/2

s = 9 cm.

by substituting the value of s in formula √ [s (s-a) (s-b) (s-c) ]  x 2

we will get,

√ [9 (9-6) (9-4) (9-8) ]  x 2

√[9 x 3 x  5 x 1]  x 2

√135 x 2

6√ 15 or 23.2379 cm

So, the area of parallelogram is 6√ 15 or 23.2379 cm

Hope this was helpful.

Hello,

A diagonal divides parallelogram into two equal parts

so area = 2* (area of triangle with sides 6cm , 4cm , 8cm)

Let the area of the Triangle be A1

then area of parallelogram is 2*A1

for traingle of Area A1,

s=(6+4+8)/2=9

Then area of Traingle A1=sqrt(s(s-a)(s-b)(s-c)

A1=sqrt(9(9-6)(9-4)(9-8))

=sqrt(9*3*5*1)

=3*sqrt(15)

=3*3.87

=11.61

Therefore the area of parallelogram is 2*A1=2*11.61=23.23

Therefore area of the parallelogram is 23.23cm2