Question : A person's salary increased from INR 8,100 to INR 9,000. What is the percentage increase in his salary?
Option 1: $9 \frac{1}{9} \%$
Option 2: $13 \frac{7}{9} \%$
Option 3: $11 \frac{1}{9} \%$
Option 4: $6 \frac{1}{9} \%$
Correct Answer: $11 \frac{1}{9} \%$
Solution : Initial salary = INR 8100 Increased salary = INR 9000 Percentage increased =$\frac{\text{Initial salary} - \text{Increased salary}}{\text{Initial salary}} \times 100$ So, the required percentage = $\frac{9000 - 8100}{8100} \times 100$ = $\frac{900}{8100} \times 100$ = $\frac{100}{9} \%$ = $11 \frac{1}{9} \%$ $\therefore$ The percentage increase in his salary is $11 \frac{1}{9} \%$ Hence, the correct answer is $11 \frac{1}{9}\%$.
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Question : A person's salary has increased from INR 7,000 to INR 12,000. What is the percentage increase in his salary?
Option 1: $61 \frac{1}{7} \%$
Option 2: $69 \frac{1}{7} \%$
Option 3: $76 \frac{4}{7} \%$
Option 4: $71 \frac{3}{7} \%$
Question : The monthly income of an employee was INR 26,500 and his monthly expenditure was INR 22,000. Next year his income increased by 20% and his expenditure increased by 15%. Find the percentage increase in his savings.
Option 1: $44 \frac{7}{9} \%$
Option 2: $44 \frac{8}{9} \%$
Option 3: $44 \frac{5}{9} \%$
Option 4: $44 \frac{4}{9} \%$
Question : If the six-digit number 479xyz is exactly divisible by 7, 11, and 13, then {(y + z) ÷ x} is equal to:
Option 1: $4$
Option 2: $\frac{11}{9}$
Option 3: $\frac{7}{13}$
Option 4: $\frac{13}{7}$
Question : What is the simplified value of $\left(1-\frac{1}{4-\frac{2}{1+\frac{1}{\frac{1}{3}+2}}}\right) \times \frac{15}{16} \div \frac{2}{3}$ of $2 \frac{1}{4}-\frac{3+4}{3^3+4^3}$
Option 1: $\frac{5}{13}$
Option 2: $\frac{4}{13}$
Option 3: $\frac{8}{13}$
Option 4: $\frac{6}{13}$
Question : Satish bought 35 notebooks for Rs. 700 and sold 28 of them for Rs. 600. Find his gain percentage.
Option 1: $7 \frac{1}{7} \%$
Option 2: $9 \frac{1}{7} \%$
Option 3: $6 \frac{1}{7} \%$
Option 4: $8 \frac{1}{7} \%$
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