95 Views

A total energy of the body excuting s.h.m isE then the kinetic energy when displacement is half of the amplitude is


Kanhaiya kumar 14th Aug, 2019
Answer (1)
siddhiarora2311_9776369 Student Expert 15th Aug, 2019

Hey Kanhaiya!

Displacement= a/2

Total energy=1/2 m* (omega)^2* (a)^2 ....(1)

KE when displacement= x is

1/2 m* (omega)^2* [(a)^2-(x)^2]

1/2 m* (omega)^2* [(a)^2-(a/2)^2]

3/4(1/2*m* (omega)^2* (a)^2) .....(2)

By dividing 2 by 1, we get: 3/4

Therefore total fraction is 3/4

Sorry to inform you but it's a career counseling website, try searching your answers on an educational forums next time.

Best of luck!

Related Questions

UPES B.Tech Admissions 2026
Apply
Ranked #43 among Engineering colleges in India by NIRF | Highest Package 1.3 CR , 100% Placements
UPES Integrated LLB Admission...
Apply
Ranked #18 amongst Institutions in India by NIRF | Ranked #1 in India for Academic Reputation by QS Rankings | 16 LPA Highest CTC
Great Lakes Institute of Mana...
Apply
Admissions Open | Globally Recognized by AACSB (US) & AMBA (UK) | 17.8 LPA Avg. CTC for PGPM 2025
Nirma University Law Admissio...
Apply
Grade 'A+' accredited by NAAC | Ranked 33rd by NIRF 2025
UPES M.Tech Admissions 2026
Apply
Ranked #45 Among Universities in India by NIRF | 1950+ Students Placed 91% Placement, 800+ Recruiters
UPES | BBA Admissions 2026
Apply
#36 in NIRF, NAAC ‘A’ Grade | 100% Placement, up to 30% meritorious scholarships
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books