Question : A wire is in the form of a square with a side of 11 cm. It is bent to form a circle. What is the radius of the circle?
Option 1: 11 cm
Option 2: 5 cm
Option 3: 9 cm
Option 4: 7 cm
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Correct Answer: 7 cm
Solution : Side of square = 11 cm Perimeter of square = 4 × side Perimeter of square = 4 × 11 = 44 cm Circumference of circle = 2π$r$ where $r$ is the radius of the circle. The perimeter of the square = Circumference of the circle ⇒ $44= 2πr$ ⇒ $44 = 2 \times{\frac{22}{7}} \times {\text{r}}$ ⇒ $r = 7$ cm Hence, the correct answer is 7 cm.
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Question : A piece of wire, when bent to form a circle, will have a radius of 84 cm. If the wire is bent to form a square, the length of one side of the square is:
Option 1: 152 cm
Option 2: 132 cm
Option 3: 168 cm
Option 4: 225 cm
Question : A solid copper sphere of radius 9 cm is hammered and moulded into a wire of radius 2 cm. What is the length of this wire?
Option 1: 224 cm
Option 2: 183 cm
Option 3: 198 cm
Option 4: 243 cm
Question : The side of an equilateral triangle is 9 cm. What is the radius of the circle circumscribing this equilateral triangle?
Option 1: $2\sqrt{3}$ cm
Option 2: $5\sqrt{3}$ cm
Option 3: $4\sqrt{3}$ cm
Option 4: $3\sqrt{3}$ cm
Question : A piece of wire 132 cm long is bent successively in the shapes of an equilateral triangle, a square, and a circle. The area will be largest in the shape of:
Option 1: Circle
Option 2: Equilateral triangle
Option 3: Square
Option 4: Equal in all the shapes
Question : The side of an equilateral triangle is 12 cm. What is the radius of the circle circumscribing this equilateral triangle?
Option 1: $6 \sqrt{3}\ \text{cm}$
Option 2: $4\sqrt{3}\ \text{cm}$
Option 3: $9 \sqrt{3}\ \text{cm}$
Option 4: $5\sqrt{3}\ \text{cm}$
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