Question : A work can be completed by N men in 15 days. 5 men leave the work after 3 days. The remaining work was completed in 18 days. What is the value of N?
Option 1: 18
Option 2: 21
Option 3: 15
Option 4: 12
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Correct Answer: 15
Solution : Let the efficiency of one man be E Total work done by N men for 15 days with efficiency of E = N × E × 15 = 15NE Total work done by N men in 3 days = 3NE The remaining work = 15NE – 3NE = 12NE After 3 days 5 men left the work. Remaining workers = (N – 5) The remaining work is completed in 18 days by (N – 5) workers, ⇒ 18 × (N – 5) × E = 12NE ⇒ 18(N – 5) = 12N ⇒ 18N – 90 = 12N ⇒ 6N = 90 ⇒ N = 15 Hence, the correct answer is 15.
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Question : 15 men can do a work in 15 days working 8 hours a day. N men can do twice the work in 20 days working 10 hours a day. What is the value of N?
Option 1: 14
Option 2: 12
Option 3: 16
Option 4: 18
Question : A work can be completed by 20 men in 50 days. 30 more men join them after 10 days of work. How many days will be saved in the completion of the work?
Option 1: 18 days
Option 2: 20 days
Option 3: 24 days
Option 4: 28 days
Question : 12 men can complete a work in 6 days working 4 hours per day. If 4 men work 8 hours per day, then in how many days the same work will be completed?
Option 1: 8 days
Option 2: 6 days
Option 3: 9 days
Option 4: 10 days
Question : 18 men can do a piece of work in 20 days. After working for 8 days, they get a notice to complete the work 4 days earlier than originally scheduled. How many more men will be required to be hired to complete the work as per the new schedule?
Option 1: 9
Option 3: 8
Option 4: 15
Question : A alone can do a piece of work in 30 days. He worked at it for 5 days and then B alone finished the remaining work in 10 days. In how many days B alone can finish the entire work?
Option 1: 12 days
Option 2: 15 days
Option 3: 10 days
Option 4: 18 days
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