Question : ABC is an equilateral triangle with a side of 12 cm. What is the length of the radius of the circle inscribed in it?
Option 1: $2 \sqrt{3}$ cm
Option 2: $8 \sqrt{3}$ cm
Option 3: $4 \sqrt{3} $ cm
Option 4: $6 \sqrt{3}$ cm
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Correct Answer: $2 \sqrt{3}$ cm
Solution : Given: ABC is an equilateral triangle with a side of 12 cm. The length of the inradius of the equilateral triangle = $\frac{\text{side}}{2\sqrt3}=\frac{12}{2\sqrt3}=2\sqrt3$ cm Hence, the correct answer is $2\sqrt3$ cm.
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Question : $\triangle ABC$ is an equilateral triangle with a side of 12 cm and AD is the median. Find the length of GD if G is the centroid of $\triangle ABC$.
Option 1: $6 \sqrt{3}$ cm
Option 2: $3 \sqrt{3} $ cm
Option 4: $2 \sqrt{3}$ cm
Question : The side of an equilateral triangle is 12 cm. What is the radius of the circle circumscribing this equilateral triangle?
Option 1: $6 \sqrt{3}\ \text{cm}$
Option 2: $4\sqrt{3}\ \text{cm}$
Option 3: $9 \sqrt{3}\ \text{cm}$
Option 4: $5\sqrt{3}\ \text{cm}$
Question : The side of an equilateral triangle is 9 cm. What is the radius of the circle circumscribing this equilateral triangle?
Option 1: $2\sqrt{3}$ cm
Option 2: $5\sqrt{3}$ cm
Option 3: $4\sqrt{3}$ cm
Option 4: $3\sqrt{3}$ cm
Question : ABC is an isosceles right-angle triangle. $\angle ABC = 90 ^{\circ}$ and AB = 12 cm. What is the ratio of the radius of the circle inscribed in it to the radius of the circle circumscribing $\triangle ABC$?
Option 1: $6–\sqrt{2}: 3 \sqrt{2}$
Option 2: $2–\sqrt{2}: \sqrt{2}$
Option 3: $6–3 \sqrt{2}: 1 \sqrt{2}$
Option 4: $6–3 \sqrt{2}: 6 \sqrt{2}$
Question : The side of an equilateral triangle is 36 cm. What is the radius of the circle circumscribing this equilateral triangle?
Option 1: $13 \sqrt{3} \mathrm{~cm}$
Option 2: $10 \sqrt{3} \mathrm{~cm}$
Option 3: $12 \sqrt{3} \mathrm{~cm}$
Option 4: $9 \sqrt{3} \mathrm{~cm}$
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