8 Views

Question : ABC is an isosceles triangle where AB = AC, which is circumscribed about a circle. If P is the point where the circle touches the side BC, then which of the following is true?

Option 1: BP = PC 

Option 2: BP > PC 

Option 3: BP < PC 

Option 4: BP = $\frac{1}{2}$ PC 


Team Careers360 22nd Jan, 2024
Answer (1)
Team Careers360 23rd Jan, 2024

Correct Answer: BP = PC 


Solution :
We know, AB, BC, and AC are tangents to the circle.
Let AB, BC, and AC touch the circle at points Q, P, and R respectively.
So, AQ = AR = a (say) (length of tangents from the same point are equal)
And BQ = BP = b (say) (length of tangents from the same point are equal)
And CP = CR = c (say) (length of tangents from the same point are equal)
Now, AB = a + b and AC = a + c
Since AB = AC, a + b = b + c
Or, a = c
Hence, the correct answer is BP = PC.

SSC CGL Complete Guide

Candidates can download this ebook to know all about SSC CGL.

Download EBook

Know More About

Related Questions

TOEFL ® Registrations 2025
Apply
Accepted by 13,000 universities worldwide | Offered in 200+ countries | 40 million people have taken TOEFL Test
Manipal Online M.Com Admissions
Apply
Apply for Online M.Com from Manipal University
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books