Question : ABCD is a square inscribed in a circle of radius $r$. Then the total area (in square units) of the portions of the circle lying outside the square is:
Option 1: $\pi (r^{2}-4)$
Option 2: $2\pi (r ^{2}-1)$
Option 3: $\pi^{2} r(r-7)$
Option 4: $r^{2}(\pi -2)$
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Correct Answer: $r^{2}(\pi -2)$
Solution :
Let the radius of the circle be $r$ units. Area of circle = $\pi r^2$ Diagonal of ABCD = BD = $2r$ units Area of square = $\frac{1}{2}\times \text{(BD)}^2$ = $\frac{1}{2}\times 4r^2$ = $2r^2$ Required difference = Area of the circle – Area of the square = $\pi r^2 - 2r^2$ = $r^2 (\pi- 2)$ sq. units Hence, the correct answer is $r^{2}(\pi -2)$.
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Question : A is the centre of a circle whose radius is 8 units, and B is the centre of a circle whose diameter is 8 units. If these two circles touch externally, then the area of the circle with diameter AB is:
Option 1: $36\pi$ sq. units
Option 2: $64\pi$ sq. units
Option 3: $144\pi$ sq. units
Option 4: $256\pi$ sq. units
Question : A circle and a square have the same area. The ratio of the side of the square to the radius of the circle will be:
Option 1: $\sqrt\pi:1$
Option 2: $1:\sqrt\pi$
Option 3: $(\pi)^2:1$
Option 4: $1:\sqrt2\pi$
Question : The areas of a circle and a square are the same. The ratio of the side of the square to the radius of the circle is:
Option 1: $2\pi :1$
Option 2: $1:\sqrt{\pi}$
Option 3: $\sqrt{\pi}:1$
Option 4: $1:\pi$
Question : The area of the square inscribed in a circle of radius 8 cm is:
Option 1: $256\;\mathrm{cm^2}$
Option 2: $250\;\mathrm{cm^2}$
Option 3: $128\;\mathrm{cm^2}$
Option 4: $125\;\mathrm{cm^2}$
Question : The area of triangle formed by the straight line $3x + 2y = 6$ and the co-ordinate axes is:
Option 1: 3 square units
Option 2: 6 square units
Option 3: 4 square units
Option 4: 8 square units
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