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an object moves along the circle with normal acceleration proportional to t power alpha. the power developed by all the forces acting on the object will have time dependence proportional to


P. Thanishka 1st Apr, 2020
Answer (1)
Megha 2nd Apr, 2020

Hello Aspirant !

As given by you in question , A = kt^x (K : Proportionality Quotient and x stands for alpha) ,

Normal Acceleration = v^2/R

Putting Acceleration value in it , v^2 = (kt^x)*R  (R : Radius)

Kinetic Energy(E) = 1/2 mv^2 = 1/2*mkt^xR

Power P = dE/dt = d(1/2*mkt^xR) / dt

Hence ,  P = mkt2R

Hope it helps !


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