34 Views

an unknown gas mass 12g(moler mass=120g)is kept in a close vessel at 1 atm and t C.if he increase temperature by 10 C.P rises by 10%.find t- a.100C b.127C c.173C d.-173C


swagatamajumder210619 7th Aug, 2022
Answer (1)
piyush263001 7th Aug, 2022

Hello,


From the Ideal Gas equation,


P V = n R T = ( given mass, w / molar mass, m ) R T


1 × V = ( 12 / 120 ) × R × (273+t)    ----- (i)


1.1 × V=  ( 12 / 120 ) × R × ( 273 + t + 10 ). ----- (ii)


Dividing equation (ii) by equation (i), we get


1.1 = (273+t+10) / ( 273+t+)

or  t = −173 degree Celsius


I hope you find the answer helpful.

Thank you.

Related Questions

MAHE Manipal M.Tech 2025
Apply
NAAC A++ Accredited | Accorded institution of Eminence by Govt. of India | NIRF Rank #4
Graphic Era (Deemed to be Uni...
Apply
NAAC A+ Grade | Among top 100 universities of India (NIRF 2024) | 40 crore+ scholarships distributed
Amity University Noida B.Tech...
Apply
Among Top 30 National Universities for Engineering (NIRF 2024) | 30+ Specializations | AI Powered Learning & State-of-the-Art Facilities
JSS University Mysore BBA Adm...
Apply
NAAC A++ Accredited| Ranked #24 in University Category by NIRF
JSS University Noida MBA 2025
Apply
170+ Recruiters Including Samsung, Zomato, LG, Adobe and many more | Highest CTC 47 LPA
UPES B.Tech Admissions 2025
Apply
Ranked #42 among Engineering colleges in India by NIRF | Highest Package 1.3 CR , 100% Placements | Last Date to Apply: 29th May
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books