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The following are the steps involved in the conversion of propanoic acid into isopropyl alcohol:

In step-1:Addition of LiAlH4  (Reducing Agent) .Corboxilic acid is converted into alcohol.

In step- 2:By dehydrating with Al2O3,We get an alkene(propene).

In step-3:By addition of Water , following markownikoffs rule,the OH- ions attaches to the least substituted corbon .i.e secondary corbon.

The following link contains the structure of the reaction:

https://drive.google.com/file/d/1VMszRBu3Zn7JHQgbcakh7stIzZZWX5Sb/view

Hope it helps you !!!