216 Views

derive the expression for a time of a flight of a particle


shashankpujar30 28th Dec, 2021
Answer (1)
masteranshu27 28th Dec, 2021

If you are asking regarding Time of Flight for a Projectile , then here is how you can derive it's equation.

Let the velocity with which the projectile was fired = V

Let the angle which the projectile makes with Horizontal = θ (theta)

So velocity of particle in Y axis = V sin θ

Formula for the Height (Displacement) achieved by an object when thrown upwards is: S =  ut + (1/2) at^2

From the above formula, displacement (S) for a projectile in Y-axis = 0 (since it goes up and then again falls back to ground).

So, 0 = ut + (1/2) at^2

⇒ 0 = V sinθt + (1/2) at^2

t = (2V sin θ)/g

So time of flight for a projectile is: T = (2V sin θ)/g



Related Questions

MAHE Manipal M.Tech 2025
Apply
NAAC A++ Accredited | Accorded institution of Eminence by Govt. of India | NIRF Rank #4
Graphic Era (Deemed to be Uni...
Apply
NAAC A+ Grade | Among top 100 universities of India (NIRF 2024) | 40 crore+ scholarships distributed
Amity University Noida B.Tech...
Apply
Among Top 30 National Universities for Engineering (NIRF 2024) | 30+ Specializations | AI Powered Learning & State-of-the-Art Facilities
JSS University Mysore BBA Adm...
Apply
NAAC A++ Accredited| Ranked #24 in University Category by NIRF
JSS University Noida MBA 2025
Apply
170+ Recruiters Including Samsung, Zomato, LG, Adobe and many more | Highest CTC 47 LPA
UPES B.Tech Admissions 2025
Apply
Ranked #42 among Engineering colleges in India by NIRF | Highest Package 1.3 CR , 100% Placements | Last Date to Apply: 29th May
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books