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Diffrentiation of parametric function


Shivam pratap singh 24th Aug, 2019
Answer (1)
Ankhi Banerjee 24th Aug, 2019
Hi,

In a parametric function, there will two equations given for example suppose

y=sin a

x= cos a, where 'a' is the parameter.

So in order to find a parametric equation, you will need to find (dy/dx)

On differentiating y and x with respect to a (since a is the parameter), we get

dy/da= cos a

dx/da= -sin a

So now we will need to find dy/dx in order to find parametric function. So,

dy/dx= (dy/da)÷(dx/da)= (cos a/-sin a)= -cot a

So -cot a is the parametric function of the 2 equation.

Following this process you can solve any parametric function.

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