Question : Directions: In the following question, select the odd letter cluster from the given alternatives.
Option 1: ACFJ
Option 2: RTWA
Option 3: NPSV
Option 4: HJMQ
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Correct Answer: NPSV
Solution : Let's check the options – First option: ACFJ; A + 2 = C; C + 3 = F; F + 4 = J Second option: RTWA; R + 2 = T; T + 3 = W; W + 4 = A Third option: NPSV; N + 2 = P; P + 3 = S; S + 3 = V Fourth option: HJMQ; H + 2 = J; J + 3 = M; M + 4 = Q
So, the third option is different from the other options as the difference between the letters is 2, 3, 3 instead of 2, 3, 4. Hence, the third option is correct.
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Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Option 1: FHJ
Option 2: LNQ
Option 3: JLN
Option 4: NPR
Option 1: JPV
Option 2: UIO
Option 3: KQW
Option 4: LRX
Option 1: UTS
Option 2: PNM
Option 3: KIH
Option 4: FDC
Option 1: DGJ
Option 2: KNQ
Option 3: RUX
Option 4: ILN
Option 1: CEAC
Option 2: FHDF
Option 3: PRMP
Option 4: TVRT
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