Question : Directions: Which two signs and two numbers should be interchanged in the following equation to make it correct? 686 − 14 × 49 + 400 ÷ 5 = 596
Option 1: 5 and 49, ÷ and −
Option 2: 686 and 5, + and –
Option 3: 14 and 49, × and –
Option 4: 14 and 5, + and ×
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Correct Answer: 5 and 49, ÷ and −
Solution : Given: 686 − 14 × 49 + 400 ÷ 5 = 596
Replace the given symbols and numbers in the options one by one with the original symbols and numbers in the given equation. First option: 5 and 49, ÷ and − = 686 ÷ 14 × 5 + 400 − 49 = 245 + 400 − 49 = 596 = R.H.S. Second option: 686 and 5, + and – = 5 + 14 × 49 – 400 ÷ 686 = 5 + 686 – 0.58 = 690.42 ≠ 596 Third option: 14 and 49, × and – = 686 × 49 – 14 + 400 ÷ 5 = 33614 – 14 + 80 = 33680 ≠ 596 Fourth option: 14 and 5, + and × 686 − 5 + 49 × 400 ÷ 14 = 686 −1405 = 719 ≠ 596
So, only the first option satisfies the R.H.S. of the given equation. Hence, the first option is correct.
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Question : Directions: Which two signs and two numbers should be interchanged in the following equation to make it correct? 189 ÷ 2 × 30 + 18 – 5 = 159
Option 1: 189, 30 and +, ÷
Option 2: 18, 30 and ÷, −
Option 3: 2, 30 and ÷, ×
Option 4: 30, 18 and –, ×
Question : Directions: Which two signs should be interchanged to make the given equation correct? 95 × 5 + 19 ÷ 2 − 21 = 36
Option 1: ÷ and ×
Option 2: + and −
Option 3: ÷ and −
Option 4: + and ×
Question : Directions: Which two signs and two numbers should be interchanged in the following equation to make it correct? 150 × 15 + 14 – 9 ÷ 2 = 6
Option 1: 9, 2, –, ×
Option 2: 9, 2, ÷, ×
Option 3: 150, 2, ÷, –
Option 4: 15, 9, +, ÷
Question : Directions: Which two signs should be interchanged to make the given equation correct? 294 + 14 × 4 ÷ 16 – 67 = 33
Option 1: + and ÷
Option 2: × and ÷
Option 3: + and –
Option 4: – and ÷
Question : Directions: Which two numbers and two signs should be interchanged to make the given equation correct? 5 + 44 − 8 × 25 = 203
Option 1: 8, 5 and −, +
Option 2: 8, 44 and −, +
Option 3: 8, 5 and −, ×
Option 4: 8, 44 and −, ×
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