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Question : E, F, G, and H are four points lying on the circumference of a circle to make a cyclic quadrilateral. If $\angle {FGH}=57^{\circ}$, then what will be the measure of the $\angle {HEF}$?

Option 1: $33^{\circ}$

Option 2: $123^{\circ}$

Option 3: $93^{\circ}$

Option 4: $143^{\circ}$


Team Careers360 25th Jan, 2024
Answer (1)
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Team Careers360 26th Jan, 2024

Correct Answer: $123^{\circ}$


Solution :
E, F, G, and H form a cyclic quadrilateral.
$\angle {FGH}=57^{\circ}$
In a cyclic quadrilateral, the sum of opposite angles is 180$^\circ$.
So, $\angle {FGH} + \angle {HEF} = 180^\circ$
⇒ $57^{\circ} + \angle {HEF} = 180^\circ$
⇒ $\angle {HEF} = 180^\circ- 57^{\circ} = 123^\circ$
Hence, the correct answer is $123^\circ$.

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