Hi,

If aluminum chloride in acidified aqueous solution forms a complex A and Al is in hybridisation state of B. Then, A is [Al (H2O)6 ] 3+ that is hexa aqua aluminium (III) ion, and B is sp3d2 hybridisation .

Aluminum chloride in aqueous solution forms a complex containing aluminum as a metal atom and water as ligands. The number of ligands is six. Thus, it is an octahedral complex and the hybridization involved is

sp3d2sp3d2

, which means it is an outer orbital complex.

Hope this helps.