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Find the equation of circle passing through two points on y-axis at distance 3 from the origin having the radius 5


saurav Kumar 18th Dec, 2018
Answer (1)
Debosmitha Bhattacharyya Student Expert 18th Dec, 2018

Hello,

The general equation of a circle with center (x0,y0) and radius r is given by:

(x−x0)2+(y−y0)2=r2

You are looking for the circle which intersects the points (0,3)(0,3) and (0,−3)(0,−3), whose radius is 55. To find the center of the circle, you need to find the point (x0,y0)(x0,y0) such that

√(x0−0)2+(y0−3)2  = √ (x0−0)2+(y0+3)2  = 5

Note that this center must necessarily be located on the x-axis: (x0,y0)=(x0,0), determined by x0,−x0, each of which will define a distinct circle.

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