Hello aspirant,

√(tan x) dx

Let tan x = t 2

⇒ sec 2 x dx = 2t dt

⇒ dx = [2t / (1 + t 4 )]dt

⇒ Integral  ∫ 2t 2 / (1 + t 4 ) dt

⇒ ∫[(t 2 + 1) + (t 2 - 1)] / (1 + t 4 ) dt

⇒ ∫(t 2 + 1) / (1 + t 4 ) dt + ∫(t 2 - 1) / (1 + t 4 ) dt

⇒ ∫(1 + 1/t 2 ) / (t 2 + 1/t 2 ) dt + ∫(1 - 1/t 2 ) / (t 2 + 1/t 2 ) dt

⇒ ∫(1 + 1/t 2 )dt / [(t - 1/t) 2 + 2] + ∫(1 - 1/t 2 )dt / [(t + 1/t) 2 -2]

Let t - 1/t = u for the first integral ⇒ (1 + 1/t 2 )dt = du

and t + 1/t = v for the 2nd integral ⇒ (1 - 1/t 2 )dt = dv

Integral
= ∫du/(u 2 + 2) + ∫dv/(v 2 - 2)

= (1/√2) tan -1 (u/√2) + (1/2√2) log(v -√2)/(v + √2)l + c

= (1/√2) tan -1 [(t 2 - 1)/t√2] + (1/2√2) log (t 2 + 1 - t√2) / t 2 + 1 + t√2) + c

= (1/√2) tan -1 [(tanx - 1)/(√2tan x)] + (1/2√2) log [tanx + 1 - √(2tan x)] / [tan x + 1 + √(2tan x)] + c

Hello there!

Greetings!

I am extremely sorry to tell you but your question is wrong as tax is not something whose integration can be found , tax  is a  contribution to state revenue, levied by the government on workers' income and business profits, or added to the cost of some goods, services, and transactions , so please let me know the correct question so that I can provide you its solution.

Thankyou