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Find the n factor for the reactant in the given reaction kclo3 - kclo4+kcl


Yash 21st Nov, 2020
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Answer (1)
sapanapatil4561 21st Nov, 2020


4 KClO3 (aq) ---> 3 KClO4 (s) + KCl (aq)

This is anoxidation-reduction(redox) reaction:

Cl (+5)+6e - Cl (-1) (reduction)
3Cl (+5) -6e - 3Cl (+7) (oxidation)

KClO 3 is both anoxidizingand areducingagent (disproportionation (dismutation)).

This is aprecipitationreaction:KClO 4 is the formed precipitate.
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21st Nov, 2020
What is the answer
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21st Nov, 2020
Yash In each case, 6 mole of electrons are exchanged whether we consider oxidation or reduction.

so n factor is 6
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