Question : Find the value of $\tan 27^{\circ} \tan 34^{\circ}+\tan 34^{\circ} \tan 29^{\circ}+\tan 29^{\circ} \tan 27^{\circ}$.
Option 1: $0$
Option 2: $–1$
Option 3: $\sqrt3$
Option 4: $1$
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Correct Answer: $1$
Solution : If $A + B + C = 90°$, then $\tan A\tan B + \tan B\tan C + \tan C\tan A = 1$ Now, 27 + 34 + 29 = 90° So, $\tan 27^{\circ} \tan 34^{\circ} + \tan 34^{\circ} \tan 29^{\circ} + \tan 29^{\circ} \tan 27^{\circ}=1$ Hence, the correct answer is 1.
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Question : The value of $\tan 5^{\circ} \tan 25^{\circ} \tan 45^{\circ} \tan 65^{\circ} \tan 85^{\circ}$ is ______.
Option 1: 4
Option 2: 3
Option 3: 1
Option 4: 2
Question : The value of $\frac{3\left(\cot ^2 47^{\circ}-\sec ^2 43^{\circ}\right)-2\left(\tan ^2 23^{\circ}-\operatorname{cosec}^2 67^{\circ}\right)}{\operatorname{cosec}^2\left(68^{\circ}+\theta\right)-\tan \left(\theta+61^{\circ}\right)-\tan ^2\left(22^{\circ}-\theta\right)+\cot \left(29^{\circ}-\theta\right)}$ is:
Option 1: –1
Option 2: 1
Option 3: 5
Option 4: 0
Question : What is the value of $\tan 6^{\circ} × \tan 45^{\circ} × \tan 84^{\circ}$?
Option 1: $1$
Option 2: $\tan 6^{\circ} \times \tan 39^{\circ}$
Option 3: $3$
Option 4: $\tan 6^{\circ}+\tan 45^{\circ}+\tan 84^{\circ}$
Question : Find the value of $\tan (–1125°)$.
Option 2: $\frac{1}{2}$
Option 3: $–1$
Option 4: $0$
Question : If $x\sin ^{2}60^{\circ}-\frac{3}{2}\sec 60^{\circ}\tan^{2}30^{\circ}+\frac{4}{5}\sin ^{2}45^{\circ}\tan ^{2}60^{\circ}=0$, then $x$ is:
Option 1: $-\frac{1}{15}$
Option 2: $–4$
Option 3: $-\frac{4}{15}$
Option 4: $–2$
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