518 Views

Galileo writes that for angles of projection of a projectile at angles (45+alpha) and (45-alpha) the horizontal ranges describe by the pro


KARSANG YANI 9th Jul, 2019
Answer (1)
NAVEEN MEENA Student Expert 9th Jul, 2019

Dear Karsang, 

For complementary angles, range will be same. Therefore, 

For angle (45°-θ), R = u2sin(90° - 2θ)/g = u2 cos 2θ/g

For angle 45°+θ), R = u2sin(90° + 2θ)/g = u2 cos 2θ/g

So, the ratio of the projectile is - 1:1

Thus answer is 1:1

All the best 

Feel free to ask for any query 

1 Comment
Comments (1)
9th Jul, 2019
Thnk you so much
Reply

Related Questions

Amity University, Noida Law A...
Apply
700+ Campus placements at top national and global law firms, corporates and judiciaries
Amity University, Noida BBA A...
Apply
Ranked amongst top 3% universities globally (QS Rankings)
VIT Bhopal University | M.Tec...
Apply
M.Tech admissions open @ VIT Bhopal University | Highest CTC 52 LPA | Apply now
Amity University | M.Tech Adm...
Apply
Ranked amongst top 3% universities globally (QS Rankings).
Graphic Era (Deemed to be Uni...
Apply
NAAC A+ Grade | Among top 100 universities of India (NIRF 2024) | 40 crore+ scholarships distributed
Great Lakes PGPM & PGDM Admis...
Apply
Admissions Open | Globally Recognized by AACSB (US) & AMBA (UK) | 17.3 LPA Avg. CTC for PGPM 2024
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books