2666 Views

Given that the displacement of an oscillating particle is given by y=A sin (Bx + Ct + D). The dimensional formula for (ABCD) is


kishorereddy07205 23rd Apr, 2020
Answer (1)
Smrity 23rd Apr, 2020

Hey,

Every term which is written inside the sin is dimensionless, thus:

Bx= M^0 L^0 T^0

which means

B= M^0 L^-1 T^0

Lt= M^0 L^0 T^0

C=M^0 L^0 T^-1

D=M^0 L^0 T^0

A=M^0 L^1 T^0

Therefore,

the dimensional formula of ABCD  is

=(L^1 L^-1 T^-1)*(M^0 L^0 T^0) = M^0 L^0 T^-1

which is the required answer.

I hope this helps.

All the best!

Related Questions

Amity University, Noida Law A...
Apply
700+ Campus placements at top national and global law firms, corporates and judiciaries
Amity University Noida B.Tech...
Apply
Among Top 30 National Universities for Engineering (NIRF 2024) | 30+ Specializations | AI Powered Learning & State-of-the-Art Facilities
Amity University Noida MBA Ad...
Apply
Amongst top 3% universities globally (QS Rankings) | Ranked among top 10 B-Schools in India by multiple publications
Amity University, Noida BBA A...
Apply
Ranked amongst top 3% universities globally (QS Rankings)
MAHE Online MBA
Apply
Apply for Online MBA from Manipal Academy of Higher Education (MAHE)
FLAME University | MBA 2026
Apply
NAAC A++ Grade | MBA program graded A** (National) by CRISIL | AACSB, ACBSP and BGA Member
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books