Question : How many 100-digit positive numbers are there?
Option 1: $9×10^{99}$
Option 2: $9×10^{100}$
Option 3: $10100$
Option 4: $11×10^{98}$
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Correct Answer: $9×10^{99}$
Solution : In any 100-digit number, the first digit cannot be 0. It will be a number from 1 to 9. The next digits can be any digit from 0 to 9. Number of 100-digit positive numbers = 9 × 10 × 10 × 10 ……………10 (99 times) = $9 × 10^{99}$ Hence, the correct answer is $9 × 10^{99}$.
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Question : Directions: If 4 × 9 × 3 = 4 and 5 × 3 × 1 = 3, then 9 × 9 × 7 = ?
Option 1: 5
Option 2: 6
Option 3: 7
Option 4: 9
Question : Directions: By Interchanging the given two numbers which of the following equations will be correct? 1 and 9
Option 1: 9 × 3 – 4 ÷ 2 + 1 = 10
Option 2: 1 + 9 × 3 – 4 ÷ 2 = 18
Option 3: 9 × 2 + 1 – 8 ÷ 4 = 12
Option 4: 9 – 1 + 6 ÷ 2 × 3 = 7
Question : Directions: By interchanging the given two signs and numbers which of the following equations will be correct? × and ÷, 7 and 9
Option 1: 9 – 7 × 2 + 6 ÷ 3 = 11
Option 2: 9 + 4 × 3 – 7 ÷ 1 = 40
Option 3: 8 × 3 ÷ 6 + 9 – 7 = 14
Option 4: 9 × 3 + 4 ÷ 2 – 7 = 18
Question : How many numbers are there from 300 to 700 which are divisible by 2, 3, and 7?
Option 1: 7
Option 2: 8
Option 3: 9
Option 4: 10
Question : Choose the option in which the numbers are in the correct ascending order.
Option 1: $\frac{4}{5}, \frac{2}{3}, \frac{1}{11}$ and $\frac{2}{9}$
Option 2: $\frac{1}{11}, \frac{2}{9}, \frac{2}{3}$ and $\frac{4}{5}$
Option 3: $\frac{2}{9}, \frac{1}{11}, \frac{4}{5}$ and $\frac{2}{3}$
Option 4: $\frac{2}{3}, \frac{4}{5}, \frac{1}{11}$ and $\frac{2}{9}$
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