Hello Aspirant,

The minimum or avergae marks that can be scored in JEE Advanced exam depends on the difficulty of the exam for that particular year.The qualifying cutoff for JEE Advanced will be determined based on the difficulty,previous year cutoff trends,Overall performance of the candidates in the exam, number of applicants and the total seats available.

To know about the previous year's minimum aggregate marks, do visit the link below.

https://engineering.careers360.com/articles/jee-advanced-cutoff

All the best!!

Hello Aspirant,

Your query is a bit unclear however I will try to clear it as well as I can. Following is the minimum eligibility criteria for a candidate in order to appear for JEE Advanced exam :

1. Performance in JEE Main 2019: You must qualify JEE Main 2019 and secure a rank among top 2,24,000 candidates (including all categories)

You will have to secure marks above the anounced cutoff marks. This year's cut off was - 89.7548849 for General, 78.2174869 for Gen EWS, 74.3166557 for OBC, 54.0128155 for SC, 44.3345172 for ST, 0.11371730 for PwD.

2. No. of attempts: You can attempt for JEE Advanced exam for 2 years only consecutively.

3. You should have appeared in class 12 exam.

4. You must not have taken admission in any IITs

5. The candidate must have passed class 12 with an aggregate of at least 75% marks. For SC/ST and PwD there is a relaxation of 10%.

Hope this helped.

All the best! :)