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how to take out mod of cos theta = A vector . B vector upon A B if A vector = 3 i cap + 4 j cap and B vector = 12 i cap + 5 j cap . explain in detail how to take out mod


jaywadmare 10th Sep, 2020
Answer (1)
ojaswiyolo Student Expert 10th Sep, 2020

Hey

I suppose it will be like

A vector into B vector is (3*12)+(4*5)=36+20= 56

AB= root under (3 square+4 square) * root under (12 sqaure + 5 square)= 5+13=18

Hence mod of cos theta will be : 56/18= 3.11(which is not possible hence I guess you got the question wrong and it should have been either -4j cap or -5 j cap(one of these)).

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