173 Views
how to take out mod of cos theta = A vector . B vector upon A B if A vector = 3 i cap + 4 j cap and B vector = 12 i cap + 5 j cap . explain in detail how to take out mod
Answer (1)
Hey
I suppose it will be like
A vector into B vector is (3*12)+(4*5)=36+20= 56
AB= root under (3 square+4 square) * root under (12 sqaure + 5 square)= 5+13=18
Hence mod of cos theta will be : 56/18= 3.11(which is not possible hence I guess you got the question wrong and it should have been either -4j cap or -5 j cap(one of these)).
Related Questions
JSS University Mysore 2025
Apply
NAAC A+ Accredited| Ranked #24 in University Category by NIRF | Applications open for multiple UG & PG Programs
Graphic Era (Deemed to be Uni...
Apply
NAAC A+ Grade | Among top 100 universities of India (NIRF 2024) | 40 crore+ scholarships distributed
DES Pune University M.Sc Admi...
Apply
Advanced curriculum designed to build expertise in specialized science domains like Data Science, Biotechnology, Physics, Chemistry, and more.
University of Southampton Del...
Apply
MSc Finance and MSc International Management Admissions 2025 Now Open | Ranked Among the Top 100 Universities in the World by QS World University R...
Sharda University Admissions ...
Apply
North India's Largest Educational Group | NIRF Ranked 86 | NAAC A+ Grade | Highest Package 1.6 Cr | Scholarships upto 100% | Pay Rs.500 instead of ...
Trending Articles/News
.jpg)
VSEP Chennai UG admissions 2024 open; apply now
31 May 2024