JEE Main 2026 Session 2 Memory Based Questions: All Shift (April 2, 4, 5, 6 & 8)
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Hi Vijay,
It is highly unpredictable and very difficult to guess the exact marks you would have scored from your percentile. I would advice you to check for the answer key uploaded by NTA to know the marks you would have scored.Yet it would be less than 100 marks but it is just an estimate I would even suggest you to give your best in the April attempt and score a decent percentile to get into an NIT or a IIIT.
You can go through the following link to know about marks vs percentile trend of previous year:
https://engineering.careers360.com/articles/jee-main-marks-vs-percentile
B.Tech/B.Arch Admissions OPEN
You can go through the following link to predict different colleges for you:
https://engineering. careers360.com/jee-main- college-predictor
Wishing you all the best for your future exams .
Use the JEE Main 2026 Rank Predictor to estimate your expected rank based on your scores or percentile and plan your college options smartly.
Hi dear,
It is quite difficult to predict your marks with the help of your percentile. But according to some aspirants you have got 57 marks in jee main 2020. Your rank will be around 156421. However your final rank will depend on number of student appear in April month exam.
Hope it helps
Hii aspirants
let me clear your doubt.
Your percentile is 82 It means 82% student of the Total student appeared for the Exam are Behind You Therefore 18% students of the Total students appeared for the exam are Ahead of You, Therefore Your calculated rank is 157404
Your Rank would change Either Your Percentile Score is Increases in the next attempt or Number of Student increases in the Next attemptIf the Number of Student Increases to 1400000 and Your percentile remain same then Your New rank would be 252000
As per Your current Performance You may be eligible for JEE Advance But the final cutoff will be released once the JEE Main April gets Over
If Your Percentile Score Increases in the Next attempt Then Your Rank would Be calculated By the Following Formula
(100 - your total percentile score (Higher of two)) X Student appeared in JEE Main/100
I hope my answer will help you out
Good luck
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