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Hello Hema
Congrats for scoring 92.23 percentile in JEE mains 2019 paper 2
You have scored good percentile and you have plus point of your category OBC .So you can get good NIT's or colleges.
From the given percentile There is a pedicted formula from our team to predict rank
B.Tech/B.Arch Admissions OPEN
Total No of students = 145386
Formula
Probable Rank= ( 100 - your NTA percentile ) x 145386 / 100
So your predicted rank = 11296 approx
Our Team predicted that the qualify cutt off would be above 85 percentile .But it just a prediction .So pleae wait till april.
I hope you get my point.
Good Luck!!!
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