Hello...

Congratulations on your percentile in the paper2 .

Your approximate rank will be around 1650 by using the rank predictor formula:

(100-percentile)*145386/100.

Here 145386 represent total no of candidates appeared for the exam.

You can check the previous years cutoff with your predicted rank so that you will be having an idea about the chances of getting the seat you wish.

Visit the below link for further details:

https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning/amp

ALL the best..

Hello aspirant, well done. 98.86 is a good score

Based on your score and previous year trends your rank will be nearer to (100−98.86)×1,45368/100=1657.You can have chances with the following colleges

NIT Rourkela

NIT patna

NIT raipur

Moulanam a ad NIT

Malavya NIT 

SPA delhi

Based on previous year cutoffs. For cutoffs of other reputed colleges you may have chance, go to

https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning/amp