Hello Ankit,

Your percentile is 87 in JEE paper 2 B Arch 2020  . So, you can calculate your rank by using the formula given below :

(100 - your total score) X 112679 /100

112679 is the number of students appeared for January exam .

According to your percentile , your rank is between 11000-15000 . You have less chance of getting admission in NIT's. Therefore , I assist you to start studying for the April Exam and score more to get high percentile.

The cutoff for various NIT's for SC category are :

1.National Institute of Technology, Calicut - 676

2.National Institute of Technology, Hamirpur - 1989

3.National Institute of Technology , Patna - 1521

4.National Institute of Technology, Bhopal - 2595

5.National Institute of Technology, Trichy - 271

6.National Institute of Technology, Nagpur - 482

7.National Institute of Technology, Jaipur - 2595

You can use college predictor tool using the below link :

https://engineering.careers360.com/jee-main-architecture-college-predictor