JEE Main 2026 Ques & Sol's: 28 Jan: Shift-2 | Shift-1 | All Shift (Session 1)
JEE Main 2026 Tools: Rank Predictor | College Predictor
Comprehensive Guide: IIT's | NIT's | IIIT's
Hello aspirant
Considering the total number of students to be 10 lakhs and using the below formula.
Rank= (total number of students -(percentile*0.01*number of students))
I believe you want to say 92.7 percentile
Your rank comes out to be 73000 so indeed you are qualified for jee advance
All the best
Use the JEE Main 2026 Rank Predictor to estimate your expected rank based on your scores or percentile and plan your college options smartly.
Application | Eligibility | Preparation Tips | Question Paper | Admit Card | Answer Key | Result | Accepting Colleges
Eligibility | Application | Exam Pattern | Admit Card | Preparation Tips | Answer Key | Result | Accepting Colleges
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile