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Nitish, your expected JEE Mains rank can be calculated using the formula:
(100-your total percentile) x 869010/100
So with 84.57 percentile, your rank would be around 134088.
Also, if the number of students increases to 12 lakh in the April session, the formula for rank calculation would change to:
(100-your total percentile) x 1200000/100
Hence your expected rank in this case would be around 185160.
Now the cutoff percentile is expected to change every year depending on the number of seats available and the number of students appearing. While it is difficult to predict the exact qualifying cutoff, a percentile of 85 or above is decent enough to qualify for JEE Advanced. You can also go through the previous years' cutoff to get an idea. In 2019, the NTA score cutoff for the Common Rank List was 89.7548849
According to your percentile, it might be difficult to clear the cutoffs for JEE Advanced. Also you won't be able to get a seat in the top NITs or IIITs with this rank. I would suggest you to sit for the April session and give your best in that exam so that your chance of qualifying JEE Mains and getting a top college increases. Solve the previous years' papers, brush up your concepts and revise thoroughly.
You can also go through our college predictor to check which colleges you are eligible for through your JEE Mains score. The link for the college predictor is:
JEE Main College Predictor – Know your College Admission Chances Based ...
All the best.
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