JEE Main 2026 Session 2 Memory Based Questions: April 2: Shift-1 | Shift 2
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Dear Aspirant,
According to percentiles mentioned .You are just qualifying Jee mains as from last year cutoff analysis.So the formula for calculating rank is
No of Student appeared/100 *(100-Nta score ).
So 869010 students appeared in this session of jee mains .
So your rank will be 94374
But the rank can vary if the no of students in April session changes to 12000 then you rank will also change .
If you want to know about college in which you are getting Admission according to your jee main score then you can visit the link mentioned below
https://engineering.careers360.com/jee-main-college-predictor
B.Tech/B.Arch Admissions OPEN
Thanks
All the very best
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