Question : If 49% of X = Y, then Y% of 50 is:
Option 1: 40% of Y
Option 2: 24.5 % of Y
Option 3: 50 % of X
Option 4: 24.5% of X
Correct Answer: 24.5% of X
Solution : $49$% of $X = Y$ ⇒ $Y = \frac{49}{100}×X$ So, $Y$% of $50 = \frac{Y}{100}×50=\frac{\frac{49}{100}×X}{100}×50=0.245X$ Required percentage = $0.245X×100$% = $24.5$% of $X$ Hence, the correct answer is 24.5% of X.
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Question : If $\frac{x}{y}+\frac{y}{x}=1$ and $x+y=2$, then the value of $x^3+y^3$ is:
Option 1: 1
Option 2: 3
Option 3: 0
Option 4: 2
Question : If $x^4+y^4=x^2 y^2$, then the value of $x^6+y^6$ is:
Option 1: 2
Option 2: 0
Option 3: 1
Option 4: 3
Question : If $x^4+x^2 y^2+y^4=133$ and $x^2-x y+y^2=7$, then what is the value of $xy$?
Option 1: 8
Option 2: 12
Option 3: 4
Option 4: 6
Question : If $x^{2}+y^{2}+\frac{1}{x^{2}}+\frac{1}{y^{2}}=4$, then the value of $x^{2}+y^{2}$ is:
Option 2: 4
Option 3: 8
Option 4: 16
Question : $\left(4 x^3 y-6 x^2 y^2+4 x y^3-y^4\right)$ can be expressed as:
Option 1: $(x+y)^4-x^4$
Option 2: $(x+y)^4-y^4$
Option 3: $(x-y)^4-x^4$
Option 4: $x^4-(x-y)^4$
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