Question : If 60% of A = 30% of B, B = 40% of C, and C = $x$% of A, the value of $x$ is:
Option 1: 200
Option 2: 500
Option 3: 800
Option 4: 300
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Correct Answer: 500
Solution : Given: 60% of A = 30% of B, B = 40% of C, and C = $x$% of A Here, C = $x$% of A ⇒ C = $\frac{x×A}{100}$ and B = 40% of C ⇒ B = $\frac{40×C}{100}$ ⇒ B = $\frac{40×x×A}{100×100}$ = $\frac{2×x×A}{500}$ Now, 60% of A = 30% of B ⇒ $\frac{60×A}{100}$ = $\frac{30×B}{100}$ ⇒ 2A = B ⇒ 2A = $\frac{2×x×A}{500}$ ⇒ $x$ = 500 So, the value of $x$ is 500. Hence, the correct answer is 500.
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Question : If $x+\frac{1}{x}=c+\frac{1}{c}$, then the value of $x$ is:
Option 1: $c,\frac{1}{c}$
Option 2: $c,c^{2}$
Option 3: $c,2c$
Option 4: $0, 1$
Question : If $(x+y)^3+8(x-y)^3=(3 x+A y)\left(3 x^2+B x y+C y^2\right)$, then the value of (A + B + C) is:
Option 1: 0
Option 2: 4
Option 3: 2
Option 4: 3
Question : If 91% of A is 39% of B, and B is x% of A, then the value of x is:
Option 1: $\frac{200}{3}$
Option 2: $\frac{700}{3}$
Option 3: $\frac{400}{3}$
Option 4: $\frac{500}{3}$
Question : If A : B = 2 : 5, B : C = 4 : 3, and C : D = 2 : 1, what is the value of A : C : D?
Option 1: 6 : 5 : 2
Option 2: 7 : 20 : 10
Option 3: 8 : 30 : 15
Option 4: 16 : 30 : 15
Question : If $a, b, c$ are real numbers and $a^{2}+b^{2}+c^{2}=2(a-b-c)-3,$ then the value of $a+b+c$ is:
Option 1: –1
Option 2: 1
Option 3: 3
Option 4: 0
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