Question : If (a – b) = 1, what is the value of (a3 – b3)?
Option 1: a2 + ab + b2
Option 2: (a + b)2 + 3ab
Option 3: a2 – ab + b2
Option 4: a2 + 2ab + b2
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Correct Answer: a2 + ab + b2
Solution : Given: a – b = 1 We know the algebraic identity, a3 – b3 = (a – b)(a2 + ab + b2) Substitute the given value in the above formula and we get, ⇒ a3 – b3 = (1)(a2 + ab + b2) So, a3 – b3 = a2 + ab + b2 Hence, the correct answer is a2 + ab + b2.
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Question : What is the value of (a + b)3 – a3 + b3?
Option 1: –3ab(a – b) + 2b3
Option 2: 3ab(a + b) + 2b3
Option 3: 3ab(a – b) + b3
Option 4: –3ab(a + b) + b3
Question : What is the value of a2 + b2 + c2 – 2ab – 2bc + 2ca?
Option 1: (2a + b + c)2
Option 2: (a – b + c)2
Option 3: (a – b – 2c)2
Option 4: (a + 2b – c)2
Question : If (a – b) = 1 and ab = 6, then what is the value of (a3 – b3)?
Option 1: 21
Option 2: 23
Option 3: 19
Option 4: 25
Question : If a + b + c = 1, ab + bc + ca = –22 and abc = –40, then what is the value of a3 + b3 + c3 ?
Option 1: 67
Option 2: –53
Option 3: –51
Option 4: 27
Question : If a3 + b3 = 152 and a + b = 8, then what is the value of ab?
Option 1: 2
Option 2: 11
Option 3: –10
Option 4: 15
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