Hello there is a mathematical solution but we can solve this problem by just imagining a simple case.
assume a vector in the direction of negative x axis and B and C vector are making theta angle with the positive direction of x-axis and are symmetrical with the x axis therefore from the given condition we can find that cos theta equal to 1/4.
now the required magnitude of a cross sea is the same value as that of sin theta and which is equal to a square root of 15 / 16
Question : If $\sin^2\theta = \cos^3\theta$, then the value of $(\cot^2\theta -\cot^6\theta)$ is:
Option 1: –1
Option 2: 0
Option 3: 2
Option 4: 1
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile